Step by step video, text & image solution for If one of the diameter of the circle , given by the equation , x^(2) + y^(2) - 4x + 6y - 12 = 0 , is a chord of a circle S , where centre is at (-3,2) , then the radius of S is by Maths experts to help you in doubts & scoring excellent marks in Class 12 exams. NCERT Solutions.2. The equation of the circle in standard (center, radius) form is: The center of the circle is: The radius of the circle is: verified. Solución Find the locus of the centres of the circle which cut the circles `x^2+y^2+4x-6y+9=0` and `x^2+y^2+4x+6y+4=0` orthogonally. Step 1.1, 7 Find the centre and radius of the circle x2 + y2 – 4x – 8y – 45 = 0 Given x2 + y2 – 4x – 8y – 45 = 0. Show transcribed image text There are 3 steps to solve this one.1. Prove that the area of the parallelogram formed by the lines 3x − 4y + a = 0, 3x − 4y + 3a = 0, 4x − 3y − a Tap for more steps Substitute (y−3)2 − 9 ( y - 3) 2 - 9 for y2 −6y y 2 - 6 y in the equation x2 +y2 −6y = 0 x 2 + y 2 - 6 y = 0. Similar Questions. Complete the square for x2 −4x x 2 - 4 x. Which statements are true? Check all that apply. A The equation of the circle whose radius is 3 and which touches internally the circle x2 + y2 - 4x - 6y - 12 = 0 at the point (-1, -1) is Q. Mathematics. Question. View Solution. The centre of unknown circle is (h,k). Add to both sides of the equation. Step 1. Ver respuesta no c vro dizculpa If one of the diameters of the circle, given by the equation, `x^2+y^2-4x+6y-12=0` , is a chord of a circle S, whose centre is at `(-3,""2)` , then th asked Dec 12, 2019 in Circles by sumitAgrawal ( 82. Show that the circles x 2 + y 2 − 4 x − 6 y − 12 = 0 and x 2 + y 2 + 6 x + 18 y + 26 = 0 touch each other. Step 1. Prove that the radii of the circles x2 + y2 = 1, x2 + y2 − 2x − 6y − 6 = 0 and x2 + y2 − 4x − 12y − 9 = 0 are in A.The center of the circle is at (-2, 3). Use the form , to find the values of , , and . Ver respuesta no c vro dizculpa If one of the diameters of the circle, given by the equation, `x^2+y^2-4x+6y-12=0` , is a chord of a circle S, whose centre is at `(-3,""2)` , then th asked Dec 12, 2019 in Circles by sumitAgrawal ( 82. What is the radius of a circle whose equation is x2+y2+8x−6y+21=0? 2 units. Use the form , to find the values of , , and . Given equations of circles are. Now complete the square, by dividing the -4 in front of the x by 2, and divide the -6 in front of the y by 2: (x - 2) 2 + (y - 3) 2 = 12 + 4 + 9 Precalculus. Join / Login.r.1. Suggest Corrections. -3x + 2y - 7 = 0. Answer link. Find the center and radius of the circle. For every input Read More. Use the form , to find the values of , , and . Tap for more steps Substitute (x+2)2 − 4 ( x + 2) 2 - 4 for x2 +4x x 2 + 4 x in the equation x2 + 4x+y2 −6y = −4 x 2 + 4 x + y 2 - 6 y = - 4. Step 1. 3x - 4y + 19 = 0 b. Q 3. Q 4. Solve. Use the form , to find the values of , , and . The quadratic formula gives two … x^2+y^2+4x-6y+12=0.t same line means image of centre w. Equation of the circle whose radius is 3 and which touches the circle x 2 + y 2 − 4 x − 6 y − 12 = 0 internally at the point ( … Hallamos centro y radio de la circunferencia x^2 + y^2 - 4x - 6y - 12 = 0👉Redes sociales:📌Facebook: ht Find the Center and Radius x^2-4x+y^2-12=0. Solve. Step 12. Our math solver supports basic math, pre-algebra, algebra, trigonometry, calculus and more. Step 2.:x+y=0 (A) L is common tangent of S_1 and S_2 (B) L is common chord of S_1 and S_2 (C) L is radical axis of S_1 and S_2 (D) L is perpendicular to the line joining the cente of S_1 & S_2 by Maths experts The Intercept made by the circle x 2 + y 2 + 2gx + 2fy + c = 0 on: I.2k points) class-12; circles; 0 votes. Step 1. Complete the square for . 4C. Given the equation of the circle is : x^2+y^2-4x-6y+9=0 Rewrite this equation into the center-radius form, x^2+y^2-4x-6y+9=0 => x^2-4x+y^2-6y=-9 => (x^2-4x+color(red)4)+(y^2-6y+color(red)9)=-9+color Number of Common Tangents to Two Circles in Different Conditions.. 2B. (h−2)x+(k+3)y−2h +3k−12= 0.2k points) Find the Center and Radius x^2+y^2-4x-6y-23=0. Consider the vertex form of a parabola. Step 1. Substitute (x−2)2 − 4 ( x - 2) 2 - 4 for The number of common tangents to the circles x2 +y2 −4x−6y−12 =0 and x2 +y2 +6x+18y+26 = 0 is.000 se pagó $15. Centres are C 1 (2, 3), C 2 = (–3, –9) ∴ Circle touch externally . The equation of the common tangent to the circles x 2 + y 2 − 4 x + 6 y − 12 = 0 and x 2 + y 2 + 6 x + 18 y + 26 = 0 at their point of contact.6k points) coordinate geometry x 2 + y 2 - 4x - 6y - 12 = 0 . Subtract from both sides of the equation. Study Materials. NCERT Solutions. x2 − 4x+y2 = 12 x 2 - 4 x + y 2 = 12 Complete the square for x2 −4x x 2 - 4 x. A. Write the standard form equation for the circle whose center is at (-2, 3) and that is tangent to the line 20x - 21y - 42 = 0. 1 answer. dna , , fo seulav eht dnif ot , mrof eht esU . (x−h)2 +(y−k)2 = r2 ( x - h) 2 + ( y - k) 2 = r 2. Tap for more steps Step 1. Step … Haz clic aquí 👆 para obtener una respuesta a tu pregunta ️ Como despejar esta ecuacion x^2+y^2-4x-6y-12=0? . Tap for more steps (x−2)2 −4 ( x - 2) 2 - 4 Trigonometría Gráfico x^2+y^2+4x-6y-12=0 x2 + y2 + 4x − 6y − 12 = 0 x 2 + y 2 + 4 x - 6 y - 12 = 0 Suma 12 12 a ambos lados de la ecuación. Explanation: 0 = x2 + y2 −4x + 6y − 12 = (x2 − 4x + 4) +(y2 + 6y +9) −25 = (x −2)2 + (y +3)2 − 52 Add 52 to both ends and transpose to get: (x −2)2 + (y −( − 3))2 = 52 This is in the form: (x −h)2 + (y −k)2 = r2 Popular Problems Precalculus Find the Center and Radius x^2-4x+y^2-12=0 x2 − 4x + y2 − 12 = 0 x 2 - 4 x + y 2 - 12 = 0 Add 12 12 to both sides of the equation.1. Complete the square for . Intercept Made by Circle on Axes. Solution: 97. 3x - 4y - 19 = 0 d. Center: Radius: Step 13. Step 1. Use the form , to find the values of , , and .r. Its Equation is: A. Find the value of using the formula.1. The variable r r represents the radius of the circle, h h represents the x-offset from the origin, and k k represents the y-offset Prove that the centres of the three circles x^2 + y^2 – 4x – 6y – 12 = 0, x^2 + y^2 + 2x + 4y – 10 = 0. the circle x^2 + y^2 - 4x + 6y - 12 = 0 .3. Tap for more steps Step 2. 1. Center: Radius: Step 13.5 isisbareb gnay kitit id 0 = 7 - y6 - x2 - 2y + 2x narakgnil gnuggnis sirag naamasreP .2. Step 2. Use the form , to find the values of , , and . View Solution. El centro y el radio de la circunferencia x2 + y2 - 2x - 14y + 5 = 0 son: Centro C y su radio Ejercicio 8: 1. View Solution Q 3 Click here:point_up_2:to get an answer to your question :writing_hand:if x 7 touches the circle x2 y2 4x 6y 12.The center of the circle is at (4, -6). The locus of the centre of a circle, which touches externally the circle x2+y2−6x−6y+14=0 and also touches the y-axis, is given by the equation. These values represent the important values for graphing and analyzing a circle. Step 2. Substitute the values of and into the formula. Solution for Find the volume generated by the equation x? + y² – 4x – 6y – 12 = 0 if it is rotated about the line 3x + 4y – 48 = 0. Step 12. Consider the vertex form of a parabola.t the circle x2 +y2 −4x+6y−12= 0. If a circle C, whose radius is 4, touches the circle x 2 + y 2 + 4 x Let a circle passing through (4, 0) touches the circle x 2 + y 2 + 4 x − 6 y − 12 = 0, then radius of circle C is: View Solution. The equation of the common tangent to the circle x 2 + y 2 − 4 x − 6 y − 12 = 0 and x 2 + y 2 + 6 x + 18 y + 26 = 0 at their point of contact is` The equations of the tangents to the circle x 2 + y 2 − 6 x + 4 y = 12 which are parallel to the straight line 4x + 3y + 5 = 0, are. Tap for more steps (x−2)2 −4 ( x - 2) 2 - 4. so the equation reads. Expert Solution Trending now This is a popular solution! First you have to complete the square with both the y and the x. = (x2 − 4x + 4) +(y2 + 6y +9) −25. Step 2. 5x + 12y + 19 = 0. Free y intercept calculator - find function's y-axis intercept step-by-step. Step 2. The number of common tangents that can be drawn to touch at least two of the circle is Persamaan garis singgung lingkaran x2 + y2 - 4x + 6y - 12 = 0 pada titik (5, 1) adalah . Salah satu persamaan garis singgung lingkaran ( x - 2 )2 + ( y + 1 )2 = 13 di titik yang.3. Step 2. A x^{2}+y^{2}-4x-6y-12=0 B x^{2}+y^{2}+3x+y+10=0 C 4x^{2}+4y^{2}-4x+12y-6=0 D 4x^{2}+4y^{2}-4x-8y-11=0 Solución 4 Calcula la ecuación de la circunferencia que tiene su centro en (2,-3) y es tangente al eje de abscisas. Consider a circle whose equation is x2 + y2 + 4x - 6y - 36 = 0. - b ± √b2 - 4(ac) 2a … y^{2}+6y+x^{2}-4x+12=0 All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Find the Center and Radius x^2+y^2-4x-10y+13=0. Determine each of the following for the circle whose equation is x2+4x+y2−6y+12=0.2. Step 2. answered Mar 14, 2020 by Sunil01 (67. The variable r r represents the radius of the circle, h h represents the x-offset from the origin, and k k represents the y-offset Prove that the centres of the three circles x^2 + y^2 - 4x - 6y - 12 = 0, x^2 + y^2 + 2x + 4y - 10 = 0. 0 votes . Complete the square for . Consider the vertex form of a parabola. Q5. Find the Center and Radius x^2+y^2-4x-12y-9=0. Find the equation of the circle which passes through the point (1, 1) If one of the diameters of the circle, given by the equation, x 2+ y 2 4 x +6 y 12=0, is a chord of a circle S, whose centre is at 3,2, then the radius of S is:A. Subtract from both sides of the equation. Step 3: Add that number to both sides x2 + 4x + 4 = 7 +4. ⇒ f = -7/2 Solve your math problems using our free math solver with step-by-step solutions. Use app Login. Step 2.ppA ni nepO .P. Complete the square for .; Koeberlein, Geralyn M. Center: Radius: Step 13. A.09. x^2 + 4x + y^2 - 6y - 25 = 0 Step by step video, text & image solution for Find thhe equation of the circle which touches x^(2) + y^(2) - 4x +6y -12 = 0 at (-1,1) internally with a radius of 2. Find the value of using the formula. asked Jul 16, 2021 in Circles by Daakshya01 (30. C. Question 931562: Determine the farthest distance from the point (3,7) to the circle x2+y2+4x-6y-12=0. Step 2. Step by step video & image solution for The circle x^(2)+y^(2)-4x-6y-12=0, x^(2)+y^(2)+6x-8y+21=0 are by Maths experts to help you in doubts & scoring excellent marks in Class 12 exams. Find the equation of the circle whose radius 3 and which touches internally the circle x 2 + y 2 − 4 x − 6 y − 12 = 0 at the point (-1, -1) Verified by Toppr. x 2+y2+4x−6y=12 Complete el cuadrado para x2+4x.r. Solve Solve for x x = 5y + 16 − 2 x = − 5y + 16 − 2, y ≥ − 516 Steps Using the Quadratic Formula Steps for Completing the Square View solution steps Solve for y y = 5(x−2)(x+6) View solution steps Graph Quiz Quadratic Equation x2 + y+ 4x −6y− 12 = 0 Similar Problems from Web Search Free math problem solver answers your algebra homework questions with step-by-step explanations. x^2 + 4x + y^2 - 6y - 12 = 0 C). graph { (x^2+y^2-4x+6y-12 If one of the diameters of the circle, given by the equation x 2 + y 2 − 4 x + 6 y − 12 = 0, is a chord of a circle S, whose centre is at (-3,2), then the radius of S is Q. Step 5: Take the square root of both sides: √(x +2)2 = √11. Step 2. This is the equation of a circle, center (−4,3) and radius = 5 Explanation: We need (a+b)2 = a2 +2ab+b2 x2+y2+4x-6y=-14 No solutions found Rearrange: Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation : Graph x^2+y^2-4x-6y-36=0. Use app Login. Add to both sides of the equation. 22 = 4. Number of common tangents depend on the position of the circle with respect to each other. Geometry. Haz clic aquí 👆 para obtener una respuesta a tu pregunta ️ Como despejar esta ecuacion x^2+y^2-4x-6y-12=0? . Complete the square for . x2 + y2 +4x−6y = 12 x 2 + y 2 + 4 x - 6 y = 12 Completa el cuadrado de x2 +4x x 2 + 4 x. Đường thẳng d' song song với đường thẳng d và chắn trên (C) một dây cung có độ dài bằng 2 3 có phương trình là: The equations of the tangents to the circle x 2 + y 2 − 6 x + 4 y = 12 which are parallel to the straight line 4x + 3y + 5 = 0, are. the circle is-. Complete the square for x2 −4x x 2 - 4 x. Use the form , to find the values of , , and . Login.3. Q2. These values represent the important values for graphing and analyzing a circle. Complete the square for . Explain. 0 = x2 + y2 −4x + 6y − 12. Add 9 9 to both sides of the equation. manueljulian2554 manueljulian2554 05. Then find the radius of given circle.2017 Matemáticas Universidad contestada Como despejar esta ecuacion x^2+y^2-4x-6y-12=0? . Center: Radius: Step 13. The number of common tangents to the circles x2+y2 4 x 6 y 12=0 and x2+y2+6 x+18 y+26=0 isA. A circle has a diameter whose ends are at (-3, 2) and (12, -6). These values represent the important values for graphing and analyzing a circle.000 a) ¿cuál fue el porcentaje de descuento que se hizo? Respuesta:Mover 12 al lado derecho de la ecuación ya que no contiene una variable. asked Jul 16, 2021 in Circles by Daakshya01 (30. Move −9 - 9 to the right side of the equation by adding 9 9 to both sides. The number of common tangents to the circles x2 +y2 −4x−6y−12 =0 and x2 +y2 +6x+18y+26 = 0 is. Join / Login. If one of the diameters of the circle, given by the equation x2+y2 4x+6y 12=0, is a chord of a circle S, whose centre is at 3,2, then the radius of S is. Guides. Show that the circles x 2 + y 2 − 4 x − 6 y − 12 = 0 and x 2 + y 2 + 6 x + 18 y + 26 = 0 touch each other. A x^{2}+y^{2}-4x-6y-12=0. Step 2. Standard VIII. Cooking Measurement Converter Cooking Ingredient Converter Cake Pan Converter See more.1.

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Tap for more steps Step 2. View Answer: Answer: Option A. The number of common tangents that can be drawn to the circles x2 +y2 −12x+8y+48 =0 and x2 +y2 −4x+2y−4 = 0 is. In the diagram, a circle centered at the origin, a right triangle, and the Pythagorean theorem are used to derive the equation of a circle, x2 + y2 = r2. Subtract from both sides of the equation. Let a circle passing through (4, 0) touches the circle x 2 + y 2 + 4 x − 6 y − 12 = 0, then radius of circle C is: Find the equation of family of circles passing through the point of intersection of the circles x 2 + y 2 − 2 x − 4 y − 4 = 0 and x 2 + y 2 − 10 x − 12 y + 40 = 0 and whose radius is 4. the equation of the circle described on this chord as diameter is. Step 2. Tap for more steps Step 2. Step 1. For the quadrilateral formed by the lines 4 y − 3 x − 1 = 0, 3 y + 4 x + 1 = 0, 4 y − 3 x − 2 = 0 and 3 y + 4 x + 2 = 0, which among the following NCERT Solutions For Class 12. Related Symbolab blog posts. We need to make this in form (x - h)2 + (y - k)2 = r2 From (1) x2 + y2 - 8x + 10y - 12 = 0 x2 - 8x + y2 + 10y - 12 = 0 (x2 - 8x) + (y2 + 10y) − 12 = 0 [x2 - The locus of the mid points of the chords of the circle `x^2+y^2+4x-6y-12=0` which subtend an angle of `pi/3`radians at its circumference is: (A) `(x-asked Apr 14, 2022 in Mathematics by Garimak (73.1. The point of contact P divides C 1 C 2 in the ratio 5 : 8 . Also find the point of contact and common tangent at this point of contact. x2 16x 23 ln3(x+1)+ x2 x+ 2 Li2(1 x) ˇ2 6 + x4 + 7x3 + x2 3x 2 (x+ 1)2 ln(x+ 1)lnx+ x2 + 2x 6 h Li3(x2) Li2(x2)lnx i 4 x5 + 26x4 + 146x3 + 316x2 + 288x+ 96 (x+ 1)2(x+ 4) G( 2; 1;x) + 8 x2 4x 6 G( 1; 2; 1;x) + 4(2x2 x 6)G( 1; 1;0;x) + 2 2x2 7x 12 G( 1;0; 1;x) (5x2 + 32x 8)G(0; 1; 1;x) 3(x 2)(x+ 4)y h G(0;y; 1;x) + 2G(y; 1;0;x) i 8y x4 + 3x3 Precalculus Write in Standard Form x^2+y^2-4x+6y-12=0 x2 + y2 − 4x + 6y − 12 = 0 x 2 + y 2 - 4 x + 6 y - 12 = 0 Add 12 12 to both sides of the equation. Equation of given circle: x2 +y2 ++16x−24y+183 = 0. The equation of the tangents to the circle x 2 + y 2 + 6 x + 6 y + 2 = 0, which is parallel to 3 x + 4 y + 8 = 0 are.2k Prove that the centres of the three circles `x^2 + y^2 - 4x - 6y - 12 = 0,x^2+y^2 + 2x + 4y -5 = 0 and x^2 + y^2 - 10x - 16y +7 = 0` are collinear. hx +ky−2(x+h)+3(y+k)−12= 0.. The main focus of the paper is on polynomials whose amoebas have the most The Distance Calculator can find distance between any two cities or locations available in The World Clock. Send us Feedback.1. B. Center: Radius: Step 13. Y-axis is given by: \(2\sqrt {{f^2} - c}\) Note: Intercepts are always positive. Consider the vertex form of a parabola. x 2 + y 2 4x 6y 12 = 0 Centre A is (2, 3) and radius 5 = PA, B (h, k) is the centre of the required circle of radius BP = 3 which touches the given circle internally at P (- 1, - 1) The radius of the circle is 5.To begin converting the equation to standard form, subtract 36 from both sides. Write in Standard Form x^2+y^2-4x-6y+4=0. x2 + y2 +4x−6y = 12 x 2 + y 2 + 4 x - 6 y = 12 Complete the square for x2 +4x x 2 + 4 x. Subtract from both sides of the equation. Find the value of using the formula. The equation of the common tangent to the circles x2 + y2 − 4x + 6y − 12 = 0 and x2 + y2 + 6x + 18y + 26 = 0 at their point of contact. The developed algorithms are used in higher dimensions for depicting sections of amoebas of polynomials in three variables. Explanation: If the equation of the circle is x2 +4x+y +2− 6y −12−0 , first of all need to complete the squares: x2 +4x+ 4+y2 −6y+9 = 12+4+9 How do you identity if the equation x2 +y2 +4x− 6y = −4 is a parabola, circle, ellipse, or hyperbola and how do you graph it? What is b in this “conic Write in Standard Form x^2+y^2+6x-4y+12=0. x 2 + y 2 − 4 x + 6 y − 12 = 0 and x 2 + y 2 + 6 x + 18 y + 26 = 0 _____. 4 Calcula la ecuación de la circunferencia que tiene su centro en (2,-3) y es tangente al eje de abscisas. Class 12 Class 12 Maths; Class 12 English; Class 12 Economics; Class 12 Accountancy; Class 12 Physics; Class 12 Chemistry; Class 12 Biology; Class 12 Computer Science (Python) Find the equation of the system of circles co-axial with the circles x^2 +y^2 +4x+2y+1=0 and x^2 +y^2 - 2x+6y-6 = 0. View Solution. and x 2 + y 2 + 6x + 18y + 26 = 0. Complete the square for . Equation of Circle with (h,k) as Center. My Notebook, the Symbolab way. x^ {\msquare} \log_ {\msquare} \sqrt {\square} \nthroot [\msquare] {\square} \le. x2 +y2 − 4x +6y − 12 = 0. So this circle has its center at the point (2,3) and radius 5. Step 2. D x2 + y2 + Dx + Ey + F = 0… Ecuación general Elementos: Centro Radio Caso I. Now complete the square, by dividing the -4 in front of the x by 2, and divide the -6 in front of the y by 2: (x - 2) 2 + (y - 3) 2 = 12 + 4 + 9 Precalculus. Number of common tangents to two circles in different conditions. Use the form , to find the values of , , and . Our math solver supports basic math, pre-algebra, algebra, trigonometry, calculus and more. Step 1: x2 + 4x = 7 (move the constant to the opposite side) Step 2: take half of the "4", and square that number. I : The equations to the direct common tangents to the circles x 2 + y 2 + 6 x + 4 y + 4 = 0, x 2 + y 2 − 2 x = 0 are y − 1 = 0, 4 x − 3 y − 9 = 0 II : The equations to the transverse common tangents to the The locus of the centre of the circle which bisects the circumferences of the circles `x^2 + y^2 = 4 & x^2 + y^2-2x + 6y + 1 =0` is : asked Oct 30, 2019 in Circles by 0 votes.3. 15 If one of the diameters of the circle, given by the equation, x 2 + y 2 − 4 x + 6 y − 12 = 0, is a chord of a circle S, whose centre is at (-3, 2), then the radius of S is: View Solution Q 2 The equations of the tangents to the circle x2 +y2 −6x+4y = 12 which are parallel to the straight line 4x + 3y + 5 = 0, are. Complete the square for . Q. Add to both sides of the equation. Popular Problems Trigonometry Graph x^2+y^2+4x-6y-12=0 x2 + y2 + 4x − 6y − 12 = 0 x 2 + y 2 + 4 x - 6 y - 12 = 0 Add 12 12 to both sides of the equation. x2 + y2 − 4x − 6y + 4 = 0 x 2 + y 2 - 4 x - 6 y + 4 = 0. 4x 2 + 4y 2 - 36x + 16y + 192 = 0. A). Try BYJU'S free classes today! B (-2, -3) No worries! We've got your back.1 petS .r. View Solution. 1. Luas bola 124 C. Use this form to determine the center and radius of the circle. So the circle is centered at (,) with a radius of . Solution Verified by Toppr First circle - solve by completing the square: x²+ y² - 4x - 6y - 12 = 0 (x² - 4x) + (y² - 6y) - 12 = 0 (x² - 4x + 4) + (y² - 6y + 9) - 25 = 0 (x-2)² + (y-3)² = 25 So this circle has its center at the point (2,3) and radius 5. First you have to complete the square with both the y and the x. berabsisi -1 adalah . Explanation: 0 = x2 + y2 −4x + 6y − 12. Use the form , to find the values of , , and . x2 + y2 −4x+6y = 12 x 2 + y 2 - 4 x + 6 y = 12 Complete the square for x2 −4x x 2 - 4 x. If one of the diameters of the circle, given by the equation, `x^2+y^2-4x+6y-12=0` , is a chord of a circle S, whose centre is at `(-3,""2)` , then th Show that the equation x^2 + y^2 - 4x + 6y - 5 = 0 represents a circle. Tap for more steps Step 2., < > ≤: ≥ ^ √: ⬅: : F _ ÷ | (* / ⌫ A: ↻: x: y = +-G Answer. Tap for more steps y^{2}+6y+x^{2}-4x+12=0 . circles; class-12; Share It On Facebook Twitter Email. Publisher: Cengage, SEE MORE TEXTBOOKS. (x −2)2 + (y +3)2 = 52. The maximumum distance would be from (,) through The equation of the circle concentric with the circle x2+y2+8x+10y−7=0 and passing through the centre of the circle x2+y2−4x−6y=0 is. 1 answer. Start by grouping together the x's and y's, and you might as well add 12 to both sides to get: (x 2 - 4x) + (y 2 - 6y) = 12. (x−h)2 +(y−k)2 = r2 ( x - h) 2 + ( y - k) 2 = r 2. Step 12.1 petS . Find the Center and Radius x^2+y^2-4x-12y-9=0.t. PART 2: MCQ from Number 51 - 100 Answer key: PART 2. x 2 + y 2 - 4x - 6y - 12 = 0. Find its centre and radius. Tap for more steps Step 2. x2 + y2 −4x−6y = −4 x 2 + y 2 - 4 x - 6 y = - 4. Step 2. The common tangent at If a circle C with center (5, 3) touches the circle x 2 + y 2 + 4 x − 6 y − 12 = 0 extrenally at a point (1, − 1) then the radius of the larger circle C is: Q. Start by grouping together the x's and y's, and you might as well add 12 to both sides to get: (x 2 - 4x) + (y 2 - 6y) = 12. (iii) If circles do not touch each other, 4 common tangents. Tap for more steps Step 2. If a circle C passing through the point (4, 0) touches the circle x2 + y2 + 4x - 6y = 12 externally at the point (1, -1), then the radius of C is: asked Feb 24, 2022 in Circles by Tarunk ( 30. \ge. Click here:point_up_2:to get an answer to your question :writing_hand:x2 y2 6x 8y 0 and x2 y2 4x. Question. Consider the circles C 1 ≡ x 2 + y 2 − 4 = 0, C 2 ≡ x 2 + y 2 − 6 x + 8 = 0, C 3 ≡ x 2 + y 2 − 8 x − 2 y + 16 = 0. Tap for more steps Step 1. Add 52 to both ends and transpose to get: (x −2)2 + (y −( − 3))2 = … Free system of non linear equations calculator - solve system of non linear equations step-by-step Find the Properties x^2+y^2+4x-6y-12=0. The equation of the common tangent to the circles x2 + y2 − 4x + 6y − 12 = 0 and x2 + y2 + 6x + 18y + … This is the form of a circle. (i) If circles touch externally ⇒C1C2 =r1+r2, 3 common tangents. View Solution Radius of larger circle is 5. Co-ordinates of P are. Pernyataan yang benar adalah A. Volume bola 288 B. B. The distance is calculated in kilometers, miles and nautical miles, and the initial compass bearing/heading from the origin to the destination. Complete the square for . Standard XII. Step by step video & image solution for For the circles S_1: x^2 + y^2-4x-6y-12 = 0 and S_2 : x^2 + y^2 + 6x + 4y-12=0 and the line L. B x^{2}+y^{2}+3x+y+10=0. If the ratio of the lengths of tangents from a point to the circles x 2 + y 2 + 4 x + 3 = 0, x 2 + y 2 − 6 x + 5 = 0 Is 1:2 then the locus of P is a circle whose centre is. Diketahui bola dengan jari-jari 6cm. Mathematics. x2 + y2 −4x−12y = 9 x 2 + y 2 - 4 x - 12 y = 9. Equation of the circle whose radius is 3 and which touches the circle x 2 + y 2 − 4 x − 6 y − 12 = 0 internally at the point ( − 1 , − 1 ) , is Hallamos centro y radio de la circunferencia x^2 + y^2 - 4x - 6y - 12 = 0👉Redes sociales:📌Facebook: ht Persamaan bayangan lingkaran x^2+y^2-6x+8y-24=0 oleh rota Jika garis lurus l= x-2y =5 diputar sejauh 90 terhadap ti Koordinat titik puncak bayangan parabola y=x^2-4x-5 oleh Garis x+2y-4=0 dirotasikan terhadap titik pusat P (1, 0) s Lingkaran L: (x-1)^2+ (y+2)^2=1 dirotasikan sebesar 135 te Titik R (-4, 2) dirotasi oleh [P (0, -2 Find the Center and Radius x^2+y^2-4x-8y-16=0.2. x^2 - 4x + y^2 + 6y - 12 = 0 B). 5C. Question. Substitute (x−2)2 − 4 ( x - 2 Write in Standard Form x^2+y^2-4x-6y+4=0. It will also display local time in each of the locations. Add 52 to both ends and transpose to get: (x −2)2 + (y −( − 3))2 = 52. View Solution. x^2. Also $$(h+1)^2+(k+1)^2=4$$ Ex 11. Step 2. so we have. x2 + y2 − 4x − 12y − 9 = 0 x 2 + y 2 - 4 x - 12 y - 9 = 0. asked Oct 21, 2022 in Circles by lolitkumarsingh ( 58. The equations to the transverse common tangents to the circles x 2 + y 2 − 4 x − 10 y + 28 = 0, x 2 + y 2 + 4 x We would like to show you a description here but the site won't allow us. Add to both sides of the equation.3. \frac {\msquare} {\msquare} The radius of the circle is 5.r. Guides. Tap for more steps Step 2. View Solution. Question. 2. Step 2. Use the form , to find the values of , , and . These values represent the important values for graphing and analyzing a circle. Solving for x0,y0,r easily we obtain. A function basically relates an input to an output, there's an input, a relationship and an output.8k points) selected Mar 15, 2020 by Mohini01 . Tap for more steps Step 2. Subtract 4 4 from both sides of the equation.2. Therefore difference in radii is 3, which is equal to distance between centres of the two circles. Complete the square for .2k points) circles; class-11; 0 votes. Step 2. Author: Alexander, Daniel C. Class 12 MATHS CIRCLES.1. Login. NCERT Solutions For Class 12. x 2 + y 2 + 4x - 6y - 12 = 0. Best answer. View Solution. ( x+2)2−4 Sustituya (x+2)…. Step 4: Factor the trinomial: (x +2)2 = 11. ISBN: 9781337614085. Therefore, h −2 1 = k+3 1 = −2h+3k−12 2.1, 8 Find the centre and radius of the circle x2 + y2 - 8x + 10y - 12 = 0 Given x2 + y2 - 8x + 10y - 12 = 0. asked Nov 6, 2019 in Mathematics by JohnAgrawal (91. Therefore the polar of P w. Step 1. x2 + y2 +4x−6y = 12 x … y^{2}+6y+x^{2}-4x-12=0 Quadratic equations such as this one can be solved by completing the square. Step 2. Step 2. Solución. to 3 x + 4 y − 14 = 0 is. Step 12. Use this form to determine the center and radius of the circle.(2) Now equation (1)&(2) are same. Following is the list of multiple choice questions in this brand new series: MCQ in Analytic Geometry: Parabola, Ellipse and Hyperbola. Complete the square for . x 2 + y 2 − 4 x + 6 y − 12 = 0, is a chord of a circle S, whose centre is at (-3, 2), then the radius of S is: Q. a. NCERT Solutions For Class 12 Physics; NCERT Solutions For Class 12 Chemistry; NCERT Solutions For Class 12 Biology; The equation of the circle which cuts orthogonally each of the three circles given below: x2 +y2 −2x+3y−7 = 0, x2 +y2+5x−5y+9 = 0 and x2 +y2 +7x−9y+29 =0.1. Save to Notebook! Sign in. Step 12. The equations of the tangents to the circle x 2 + y 2 - 4x - 6y - 12 = 0 and parallel to 4x - 3y = 1 are. Complete the square for y2 −6y y 2 - 6 y. Step 1. Step 2.2017 Matemáticas Universidad contestada Como despejar esta ecuacion x^2+y^2-4x-6y-12=0? . 3D. Add 9 9 to both sides of the equation. Q3. en. This is the form of a circle.. x 2 + y 2 4x 6y 12 = 0 Centre A is (2, 3) and radius 5 = PA, B (h, k) is the centre of the required circle of radius BP = 3 which touches the given circle internally at P (- 1, - 1) Write in Standard Form x^2+y^2+6x-4y+12=0. The equation of the circle whose radius is 3 and which touches internally the circle x 2 + y 2 − 4 x − 6 y − 12 = 0 at the point ( − 1 , − 1 ) is The equation of the common tangent to the circles x 2 + y 2 − 4 x + 6 y − 12 = 0 and x 2 + y 2 + 6 x + 18 y + 26 = 0 at their point of contact. C 4x^{2}+4y^{2}-4x+12y-6=0. This is the form of a circle. Step 12. C.

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Similar Questions. Equation of common tangent is S 1 – S 2 = 0 –10x – 24y – 38 = 0 . Do the same for the second circle: x² + y² + 6x + 18y + 26 = 0 (x² + 6x) + (y² + 18y) + 26 = 0 where the distance d(X, Y) between two points X, Y is defined to be the length of smaller arc on the greater circle passing through the two points, and the spherical angle \(\sphericalangle APB\) is defined to be the ordinary angle \(\angle XPY\) where XP, YP are the tangents to the arcs AP, BP (respectively). Solución. Q 3. 1 answer. x2+y2-2x-4y-11=0 No solutions found Step by step solution : Step 1 :Equation at the end of step 1 : x2 - 2x + y2 - 4y - 11 = 0 Step 2 :Solving a Single Variable Equation : How do you find the radius of the circle x2 + y2 − 4x + 6y − 12 = 0 ? r = 5 in (x−2)2 +(y+3)2 = 52 Explanation: The circle equation can be arranged as (x−x0)2 +(y Click here:point_up_2:to get an answer to your question :writing_hand:the radius of the circle x2 y2 4x 6y 13. Ex 11. Complete the square for . Co–ordinates of P are. Step 1. In [], Guo et al. Tap for more steps (x+2)2 −4 ( x + 2) 2 - 4 Solve x^2+y^2-4x+6y-12=0 | Microsoft Math Solver Solve Solve for x Steps Using the Quadratic Formula Steps for Completing the Square View solution steps Solve for y Steps Using the Quadratic Formula Steps for Completing the Square View solution steps Graph Quiz Quadratic Equation 5 problems similar to: Examples Quadratic equation Trigonometry Solve x^2+y^2+4x-6y+12=0 | Microsoft Math Solver Solve Solve for x Steps Using the Quadratic Formula Steps for Completing the Square View solution steps Solve for y Steps Using the Quadratic Formula Steps for Completing the Square View solution steps Graph Quiz Quadratic Equation 5 problems similar to: Examples Quadratic equation Trigonometry Popular Problems Precalculus Find the Domain and Range x^2+y^2+4x+6y-12=0 x2 + y2 + 4x + 6y - 12 = 0 Use the quadratic formula to find the solutions. 5 √3B. If one of the diameter of the circle, given by the equation, x 2 + y 2-4x +6y - 12 = 0, is a chord of a circle S, The centre of the circle x 2 + y 2 - 4x - 6y - 12 = 0 is . 10 D. Ukuran volume bola lebih besar daripada luas bola D. Add 0 0 and 9 9. Use app Login. Q2. Step 1. and x 2 + y 2 + 6x + 18y + 26 = 0. Chord of Contact. D. Verified answer. Center: Radius: Step 13. x2 + y2 − 4x − 12y − 9 = 0 x 2 + y 2 - 4 x - 12 y - 9 = 0. The quadratic formula gives two … Popular Problems Precalculus Find the Domain and Range x^2+y^2+4x+6y-12=0 x2 + y2 + 4x + 6y - 12 = 0 Use the quadratic formula to find the solutions. X-axis is given by: \(2\sqrt {{g^2} - c}\) II. Ukuran luas bola lebih besar daripada volume bola Cho đường tròn (C) x 2 + y 2 - 2x + 6y + 6= 0 và đường thẳng d: 4x -3y + 5= 0. Tap for more steps Step 2. Find the value of using the formula. View Solution. Consider the vertex form of a parabola.09. Match the values in this circle to those of the standard form. Add to both sides of the equation. Q4. = (x −2)2 + (y +3)2 − 52. The number of common tangents to the following pairs of circles x2 +y2 = 4,x2 +y2 −6x−8y+16 = 0 is. These values represent the important values for graphing and analyzing a circle. Complete the square for . = (x −2)2 + (y +3)2 − 52.2k points) Find the Center and Radius x^2+y^2-4x-6y-23=0. 1 answer. The correct option is C 3. Find the equation of circle circumscribing the quadrilateral formed by four lines 3x + 4y − 5 = 0, 4x − 3y − 5 = 0, 3x + 4y + 5 = 0 and 4x − 3y + 5 = 0. (ii) If circles touch internally ⇒ C1C2= r2−r1, 1 common tangents.2. Class 12 Class 12 Maths; Class 12 English; Class 12 Economics; Class 12 Accountancy; Class 12 Physics; Class 12 Chemistry; Class 12 Biology; Class 12 Computer Science (Python) Find the equation of the system of circles co-axial with the circles x^2 +y^2 +4x+2y+1=0 and x^2 +y^2 – 2x+6y–6 = 0.t. After reflection also, the radius of circle does not change. Q5. Enter a problem Cooking Calculators. -x + y + 2 - 2x - 1 + y - 8 = 0. x2 + y2 −4x−12y = 9 x 2 + y 2 - 4 x - 12 y = 9. The … Length of tangent =sqrt21 unit The center-radius form of the circle equation is given by : (x-h)^2+(y-k)^2=r^2 where h and k are the coordinates of the center of the circle, and r is the radius. The common tangent at If a circle C with center (5, 3) touches the circle x 2 + y 2 + 4 x − 6 y − 12 = 0 extrenally at a point (1, − 1) then the radius of the larger circle C is: Q. r=5 in (x-2)^2+ (y+3)^2=5^2 The circle equation can be arranged as (x-x_0)^2+ (y-y_0)^2=r^2 in which x_0,y_0 Ex 11. Q5. This is in the form: (x −h)2 + (y −k)2 = r2. Tap for more steps (x−2)2 −4 ( x - 2) 2 - 4. Use this form to determine the center and radius of the circle.4k points) Graph x^2+y^2-4x=0. View Solution. Step 2.t that line without changing radiusx2 +y2 −6x−4y+12= 0Centre = (3,2) Radius= 1Image of (3,2) w.3. Add to both sides of the equation. Example: 2x-1=y,2y+3=x. Substitute (x−2)2 − 4 ( x - 2 x²+ y² - 4x - 6y - 12 = 0 (x² - 4x) + (y² - 6y) - 12 = 0 (x² - 4x + 4) + (y² - 6y + 9) - 25 = 0 (x-2)² + (y-3)² = 25. Tap for more steps Step 2. Explanation: If the equation of the circle is x2 +4x+y +2− 6y −12−0 , first of all need to complete the squares: x2 +4x+ 4+y2 −6y+9 = 12+4+9 How … Free math problem solver answers your algebra homework questions with step-by-step explanations. Use the form , to find the values of , , and . Consider the vertex form of a parabola. The centre and radius of the circle x 2 + y 2 + 4x - 6y = 5 is: View Solution. The equation of the circle concentric with the circle x 2 + y 2 + 8 x + 10 y The image of circle w. These values represent the important values for graphing and analyzing a circle. 1: 2: 3: 4: 5: 6: 7: 8: 9: 0. Complete the square for . investigated the Fermat-Torricelli problem of triangles on the We expose methods and algorithms for computation and visualization of amoebas of bivariate polynomials, their contours and compactified versions. View Solution. = (x2 − 4x + 4) +(y2 + 6y +9) −25. Step 1. 1 answer. Consider the vertex form of a parabola.To complete the square for the x terms, add 4 to both sides. 2) un producto que inicialmente costaba $18. Graph functions, plot points, visualize algebraic equations, add sliders, animate graphs, and more.2. Move −4 - 4 to the right side of the equation by adding 4 4 to both sides. Tap for more steps (x−2)2 −4 ( x - 2) 2 - 4 Find the Properties x^2+y^2+4x-6y-12=0. D 4x^{2}+4y^{2}-4x-8y-11=0. 1 Answer George C. Tap for more steps Step 2. 3x + 4y + 19 = 0. Step 2. asked Dec 12, 2019 in Circles by sumitAgrawal (82. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction. asked Nov Find the length of the chord of the circle x 2 + y 2 + 4x + 6y - 12 = 0 and x + 4y - 6 = 0. Step 2.t x+y−1 =0x−3 1 = y−2 1 = −2 (3+2−1) 11 +12 =−4x = −1, y = −2Then equation of image of circle is(x+1)2 +(y+2)2 = (1)2⇒ x2 +y2 +2x+4y+4 = 0. 3x+y-19=0 c. The equations of the tangents to the circle x 2 + y 2 - 4x - 6y - 12 = 0 and parallel to 4x - 3y = 1 are.6k points) class-12; circle; 0 votes. Tap for more steps Step 2. Complete the square for x2 +4x x 2 + 4 x. Solution. Standard XII. x 2 + y 2 − 4 x + 6 y − 12 = 0, is a chord of a circle S, whose centre is at (-3, 2), then the radius of S is: View Solution. y=\frac{-6±\sqrt{6^{2}-4\left(x^{2}-4x+12\right)}}{2} x^{2}+y^{2}+4x-6y+12=0. The point of contact P divides C 1 C 2 in the ratio 5 : 8 . Do the same for the second circle: x 2 + y 2 − 4 x + 6 y − 12 = 0 and x 2 + y 2 + 6 x + 18 y + 26 = 0 _____. Math notebooks have been around for hundreds of years. Match the values in this circle to those of the standard form. 5x + 12y + 19 = 0. The equation of the circle passing through the point of intersection of the circles x^2 + y^2 - 4x - 2y = 8 and x^2 + y^2 - 2x Length of tangent =sqrt21 unit The center-radius form of the circle equation is given by : (x-h)^2+(y-k)^2=r^2 where h and k are the coordinates of the center of the circle, and r is the radius. Q2. You write down problems, solutions and notes to go back Read More. Center: Radius: Step 13. Example: Solve x2 +4x −7 = 0. Class 12 MATHS CIRCLE. Study Materials. Centres are C 1 (2, 3), C 2 = (-3, -9) ∴ Circle touch externally . Solve. Find the Center and Radius x^2+y^2+8x-6y-24=0. 5 √2. Step 2.1, 7 Find the centre and radius of the circle x2 + y2 - 4x - 8y - 45 = 0 Given x2 + y2 - 4x - 8y - 45 = 0. Also find the point of contact and common tangent at this point of contact. Question. Ejemplo. Online Questions and Answers in Analytic Geometry: Parabola, Ellipse and Hyperbola Series. Add to both sides of the equation. Solve your math problems using our free math solver with step-by-step solutions. x 2 + y 2 + 6 x + 8 y = 0 and x 2 + y 2 − 4 x − 6 y − 12 = 0 are the equation of the two circle Equation of one of their common tangent is. In order to complete the square, the equation must first be in the form … y^{2}-6y+x^{2}+4x+12=0 All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Find the value of using the formula. x+y−2 = 0. View Solution. Q3. Add to both sides of the equation. Dada la ecuación general, encontrar los elementos, el centro y el radio.0=4+y6-x4+2y+2x . Q.2k points) circles; class-11; 0 votes. Given the equation of the circle is : x^2+y^2-4x-6y+9=0 Rewrite this equation into the center-radius form, x^2+y^2-4x-6y+9=0 => x^2-4x+y^2-6y=-9 => (x^2 … Number of Common Tangents to Two Circles in Different Conditions. The equation of common tangent to the circles x2 +y2 =4 and x2 +y2 −6x−8y−24 = 0 is. Step 12. The equation of the common tangent to the circles x 2 + y 2 − 4 x + 6 y − 12 = 0 and x 2 + y 2 + 6 x + 18 y + 26 = 0 at their point of contact.1. Use the form , to find the values of , , and .1. Verified by Toppr. Login. Tap for more steps (x−2)2 −4 ( x - 2) 2 - 4. the standard form of the equation of a circle with centre (h,k) = (2, − 3) and radius r = 5. Complete the square for x2 −4x x 2 - 4 x. Solution.y rof evlos dna alumrof citardauq eht otni 21 - x4 + 2x = c dna ,6 = b ,1 = a seulav eht etutitsbuS a2 )ca(4 - 2b√ ± b - .3. Click here👆to get an answer to your question ️ Find the pole of the line x + y + 2 = 0 w.2 petS spets erom rof paT . Equation of common tangent is S 1 - S 2 = 0 -10x - 24y - 38 = 0 . x0 = 2,y0 = − 3,r = 5. Find the value of using the formula. manueljulian2554 manueljulian2554 05. If the equation of a circle is λx^2 + (2λ - 3)y^2 - 4x + 6y - 1 = 0, then the coordinates of centre are. A (-2 , 3) No worries! We've got your back. Jan 19, 2016 Rearrange into the standard form of the equation of a circle with centre (2, −3) and radius 5.Popular Problems Trigonometry Graph x^2+y^2+4x-6y-12=0 x2 + y2 + 4x − 6y − 12 = 0 x 2 + y 2 + 4 x - 6 y - 12 = 0 Add 12 12 to both sides of the equation. x 2 + y 2 + 4x + 6y - 12 = 0. Persamaan bayangan lingkaran x^2+y^2-6x+8y-24=0 oleh rota Jika garis lurus l= x-2y =5 diputar sejauh 90 terhadap ti Koordinat titik puncak bayangan parabola y=x^2-4x-5 oleh Garis x+2y-4=0 dirotasikan terhadap titik pusat P (1, 0) s Lingkaran L: (x-1)^2+ (y+2)^2=1 dirotasikan sebesar 135 te Titik R (-4, 2) dirotasi oleh [P (0, -2 Find the Center and Radius x^2+y^2-4x-8y-16=0. Coordenadas del centro de la circunferencia: x2 + y2 + 4x - 6y + 12 = 0 The equation of the circle concentric with the circle x 2 + y 2 + 8 x + 10 y − 7 = 0 and passing through the centre of the circle x 2 + y 2 − 4 x − 6 y = 0 is View Solution Q 3 Solve an equation, inequality or a system. PART 1: MCQ from Number 1 - 50 Answer key: PART 1.1. NCERT Solutions For Class 12 Physics; NCERT Solutions For Class 12 Chemistry; NCERT Solutions For Class 12 Biology; the equation of a chord of the circle x^2+y^2+4x-6y=0 is given by x+2y=0 . Q.3x+4y-19=0 e. Guides.6k points) coordinate geometry x 2 + y 2 – 4x – 6y – 12 = 0 . by Maths experts to help you in doubts & scoring excellent marks in Class 12 exams. Toca para ver más pasos (x+2)2 −4 ( x + 2) 2 - 4 Free system of non linear equations calculator - solve system of non linear equations step-by-step Explore math with our beautiful, free online graphing calculator. Q5. Given equation of polar-. Answer by Fombitz (32387) ( Show Source ): You can put this solution on YOUR website! Complete the square to find the equation of the circle. Add to both sides of the equation. Calculation: Given that, x 2 + y 2 + 4x - 7y + 12 = 0 ----(1) On comparing equation (1) with standard equation of circle, we will get. D.r. asked Oct 21, 2022 in Circles by lolitkumarsingh ( 58. If one of the diameter of the circle, given by the equation, x 2 + y 2 -4x +6y - 12 = 0, is a chord of a circle S, whose centre is at ( -3,2), then the radius of S is: Find the equation of the circle whose radius 3 and which touches internally the circle x 2 + y 2 − 4 x − 6 y − 12 = 0 at the point (-1, -1) Verified by Toppr.1.1. Step 1. Study Materials. Mathematics. x 2 + y 2 + 4x - 6y + 12 = 0. Prove that the centres of the three circles x2 + y2 − 4x − 6y − 12 = 0, x2 + y2 + 2x + 4y − 10 = 0 and x2 + y2 − 10x − 16y − 1 = 0 are collinear. Idea; Lets find the reflection of centre of this circle with respect to the given line equation. Find the volume generated by the equation x² + y² - 4x - 6y - 12 = 0 if it is rotated about the line Зх + 4y — 48 3D 0.1. Thus finally knowing the centre of reflected circle and its radius Prove that the centres of the three circles x2 + y2 − 4x − 6y − 12 = 0, x2 + y2 + 2x + 4y − 10 = 0 and x2 + y2 − 10x − 16y − 1 = 0 are collinear. - 6 ± √62 - 4 ⋅ (1 ⋅ (x2 + 4x - 12)) 2 ⋅ 1 Simplify. Join / Login. Yes, the distance from (-2, 0) to (1, ) is 4 units. Find the volume generated by the equation x2 + y2 - 4x - 6y - 12 = 0 if it is rotated about the line 3x + 4y - 48 = 0.(1) Let P (h,k) be the pole of line x +y = 2 w. ⎧⎪ ⎨⎪⎩−2x0 = −4 −2y0 = 6 x2 0 +y2 0 − r2 = −12. These values represent the important values for graphing and analyzing a circle. Try BYJU'S free classes today! C (2,3) Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses. 1 Answer. Use the form , to find the values of , , and . All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}.